The Solution
Calculation: Depressed Cubic Calculator
Depressed Cubic Calculator
Enter your polynomial coefficients above and click "Depress Cubic" to see results.Cubic Equation Solver
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Input your cubic equation's coefficients to eliminate the x² term and obtain the depressed form t³ + pt + q = 0.
Calculation: Depressed Cubic Calculator
Depressed Cubic Calculator
Enter your polynomial coefficients above and click "Depress Cubic" to see results.The Treatise
The Formula
The Method
The Illustration
The Deep Dive
The transformation is named for Ehrenfried Walther von Tschirnhaus, who published it in 1683 as part of a grand program to solve all polynomial equations by clever substitutions. His program ultimately failed for the quintic, but the cubic case survived as an indispensable tool. The idea is disarmingly simple: because the x² coefficient is, up to a factor, the sum of the roots, shifting the variable by the average root centers the whole configuration at the origin. What looks like an algebraic trick is really a geometric recentering.
Why does x = t − b/3a kill exactly the quadratic term? Expand a(t − b/3a)³ + b(t − b/3a)² + c(t − b/3a) + d and collect the t² coefficient: from the cubic term comes 3a(−b/3a) = −b, from the quadratic term comes +b. They cancel exactly, and no other choice of shift does this. The t and constant terms then assemble themselves into p and q. It is worth doing this expansion once by hand: the cancellation feels like watching a lock click open.
The formulas p = (3ac − b²)/3a² and q = (2b³ − 9abc + 27a²d)/27a³ look intimidating, but each has meaning. The numerator of p is, up to sign, the discriminant of the quadratic part, measuring how "spread" the equation is. The expression for q mixes all four coefficients because the constant term of the shifted equation genuinely depends on everything. Notice the denominators are powers of a: for a monic cubic they vanish into p = 3c − b² over 3 style simplicity, which is why textbooks usually present the monic case first.
Depressing also centers the graph. The inflection point of ax³ + bx² + cx + d sits at x = −b/3a, precisely the shift amount, so the depressed cubic's graph is symmetric about its inflection point at the origin. Our inflection point calculator locates this center, and the graphing tool shows the before-and-after: the same S-curve, slid horizontally until its midpoint sits on the y-axis. This symmetry is why the depressed form is easier to analyze qualitatively.
The same spirit removes terms from higher-degree equations: a quartic can be depressed to t⁴ + pt² + qt + r = 0, which is Ferrari's entry point. For the quintic, the Bring-Jerrard transformation reduces it to t⁵ + pt + q = 0, yet no radical formula finishes the job, as Abel and Ruffini proved. The depressed cubic is thus the sweet spot of the whole theory: the hardest equation that a shift plus radicals can completely conquer.
The Applications
Every application of Cardano's method begins here: no depressed form, no formula. The reduction is so standard that computer algebra systems perform it silently before displaying Cardano's steps. Mastering this one transformation opens up the entire classical solution theory of the cubic.
Centering a cubic at its inflection point makes sketching dramatically easier: the turning points become symmetric about the origin, and the number of real roots can be read from the values at those symmetric points. Graphing tools use this internally when choosing viewing windows.
When coefficients vary wildly in magnitude, the shift often produces smaller, better-balanced p and q. Numerical solvers converge faster and roundoff error shrinks, because the computation no longer mixes huge and tiny terms. Preconditioning by depression is a quiet workhorse of numerical libraries.
Instructors use depression to split a frightening problem into two manageable ones: a routine substitution, then a cleaner equation. Students who can depress a cubic on sight have internalized the relationship between coefficients and roots that Vieta's formulas describe.
Physicists routinely shift coordinates to remove linear or quadratic terms: completing the square is the quadratic version of this exact move. In perturbation theory and normal-mode analysis, centering the coordinate system at the natural midpoint simplifies every subsequent expansion.
The Cautions
Forgetting to shift back: The depressed cubic has different roots than the original: each is shifted by −b/3a. Solving t³ − t = 0 gives t = 0, ±1, but the original equation's roots are x = 2, 3, 1. Always apply x = t − b/3a at the end.
Sign error in the shift: The substitution is x = t − b/3a, with b carrying its own sign. For x³ − 6x² + …, b = −6, so the shift is t + 2, not t − 2. Write b with its sign before substituting.
Arithmetic slips in p and q: The q formula has three signed terms and powers up to b³. It is the most error-prone hand computation in elementary cubic theory. Let the tool compute them, or check by expanding back.
Dividing by a zero leading coefficient: If a = 0 the equation is not cubic and the formulas divide by zero. Confirm the degree is genuinely three before depressing.
Mixing discriminant formulas: The five-term discriminant belongs to the general cubic; the two-term version Δ = −(4p³ + 27q²) belongs to the depressed one. Applying the short formula to unshifted coefficients gives a wrong sign and wrong verdict.
The Reference
The Questions
A cubic with no x² term: t³ + pt + q = 0. Every cubic ax³ + bx² + cx + d = 0 can be converted to this form by the shift x = t − b/3a.
Because every classical solution method, especially Cardano's method, requires the depressed form. It also simplifies the discriminant and centers the graph at its inflection point.
Yes, provided the leading coefficient a is nonzero. The shift −b/3a always exists and always kills the quadratic term exactly.
Fixed combinations of the original coefficients: p = (3ac − b²)/3a² and q = (2b³ − 9abc + 27a²d)/27a³. They carry all the equation's information in compressed form.
Yes. Expanding a(t + h)³ + b(t + h)² + … shows the t² coefficient vanishes only when h = −b/3a. Any other shift leaves a quadratic term behind.
It shifts each root by −b/3a but preserves their relationships: differences, multiplicities, and reality are unchanged. See how roots relate with our roots relationship calculator.
Yes, with Cardano's formula, which was designed for exactly this form. Many depressed cubics also factor nicely by inspection.
It collapses from five terms to two: Δ = −(4p³ + 27q²). Verify the classification with our discriminant calculator.